Metamath Proof Explorer


Theorem decsplit0

Description: Split a decimal number into two parts. Base case: N = 0 . (Contributed by Mario Carneiro, 16-Jul-2015) (Revised by AV, 8-Sep-2021)

Ref Expression
Hypothesis decsplit0.1 𝐴 ∈ ℕ0
Assertion decsplit0 ( ( 𝐴 · ( 1 0 ↑ 0 ) ) + 0 ) = 𝐴

Proof

Step Hyp Ref Expression
1 decsplit0.1 𝐴 ∈ ℕ0
2 1 decsplit0b ( ( 𝐴 · ( 1 0 ↑ 0 ) ) + 0 ) = ( 𝐴 + 0 )
3 1 nn0cni 𝐴 ∈ ℂ
4 3 addid1i ( 𝐴 + 0 ) = 𝐴
5 2 4 eqtri ( ( 𝐴 · ( 1 0 ↑ 0 ) ) + 0 ) = 𝐴