Metamath Proof Explorer


Theorem dedth3h

Description: Weak deduction theorem eliminating three hypotheses. See comments in dedth2h . (Contributed by NM, 15-May-1999)

Ref Expression
Hypotheses dedth3h.1 ⊢ ( 𝐴 = if ( 𝜑 , 𝐴 , 𝐷 ) → ( 𝜃 ↔ 𝜏 ) )
dedth3h.2 ⊢ ( 𝐵 = if ( 𝜓 , 𝐵 , 𝑅 ) → ( 𝜏 ↔ 𝜂 ) )
dedth3h.3 ⊢ ( 𝐶 = if ( 𝜒 , 𝐶 , 𝑆 ) → ( 𝜂 ↔ 𝜁 ) )
dedth3h.4 ⊢ 𝜁
Assertion dedth3h ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 )

Proof

Step Hyp Ref Expression
1 dedth3h.1 ⊢ ( 𝐴 = if ( 𝜑 , 𝐴 , 𝐷 ) → ( 𝜃 ↔ 𝜏 ) )
2 dedth3h.2 ⊢ ( 𝐵 = if ( 𝜓 , 𝐵 , 𝑅 ) → ( 𝜏 ↔ 𝜂 ) )
3 dedth3h.3 ⊢ ( 𝐶 = if ( 𝜒 , 𝐶 , 𝑆 ) → ( 𝜂 ↔ 𝜁 ) )
4 dedth3h.4 ⊢ 𝜁
5 1 imbi2d ⊢ ( 𝐴 = if ( 𝜑 , 𝐴 , 𝐷 ) → ( ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) ↔ ( ( 𝜓 ∧ 𝜒 ) → 𝜏 ) ) )
6 2 3 4 dedth2h ⊢ ( ( 𝜓 ∧ 𝜒 ) → 𝜏 )
7 5 6 dedth ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )
8 7 3impib ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 )