Metamath Proof Explorer


Theorem deg1vsca

Description: The degree of a scalar times a polynomial is exactly the degree of the original polynomial when the scalar is not a zero divisor. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses deg1addle.y ⊢ 𝑌 = ( Poly1 ‘ 𝑅 )
deg1addle.d ⊢ 𝐷 = ( deg1 ‘ 𝑅 )
deg1addle.r ⊢ ( 𝜑 → 𝑅 ∈ Ring )
deg1vsca.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
deg1vsca.e ⊢ 𝐸 = ( RLReg ‘ 𝑅 )
deg1vsca.p ⊢ · = ( ·𝑠 ‘ 𝑌 )
deg1vsca.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐸 )
deg1vsca.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
Assertion deg1vsca ( 𝜑 → ( 𝐷 ‘ ( 𝐹 · 𝐺 ) ) = ( 𝐷 ‘ 𝐺 ) )

Proof

Step Hyp Ref Expression
1 deg1addle.y ⊢ 𝑌 = ( Poly1 ‘ 𝑅 )
2 deg1addle.d ⊢ 𝐷 = ( deg1 ‘ 𝑅 )
3 deg1addle.r ⊢ ( 𝜑 → 𝑅 ∈ Ring )
4 deg1vsca.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
5 deg1vsca.e ⊢ 𝐸 = ( RLReg ‘ 𝑅 )
6 deg1vsca.p ⊢ · = ( ·𝑠 ‘ 𝑌 )
7 deg1vsca.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐸 )
8 deg1vsca.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
9 eqid ⊢ ( 1o mPoly 𝑅 ) = ( 1o mPoly 𝑅 )
10 2 deg1fval ⊢ 𝐷 = ( 1o mDeg 𝑅 )
11 1on ⊢ 1o ∈ On
12 11 a1i ⊢ ( 𝜑 → 1o ∈ On )
13 1 4 ply1bas ⊢ 𝐵 = ( Base ‘ ( 1o mPoly 𝑅 ) )
14 1 9 6 ply1vsca ⊢ · = ( ·𝑠 ‘ ( 1o mPoly 𝑅 ) )
15 9 10 12 3 13 5 14 7 8 mdegvsca ⊢ ( 𝜑 → ( 𝐷 ‘ ( 𝐹 · 𝐺 ) ) = ( 𝐷 ‘ 𝐺 ) )