Metamath Proof Explorer


Definition df-fldext

Description: Definition of the field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023)

Ref Expression
Assertion df-fldext /FldExt = { ⟨ 𝑒 , 𝑓 ⟩ ∣ ( ( 𝑒 ∈ Field ∧ 𝑓 ∈ Field ) ∧ ( 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) ) ∧ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 ) ) ) }

Detailed syntax breakdown

Step Hyp Ref Expression
0 cfldext ⊢ /FldExt
1 ve ⊢ 𝑒
2 vf ⊢ 𝑓
3 1 cv ⊢ 𝑒
4 cfield ⊢ Field
5 3 4 wcel ⊢ 𝑒 ∈ Field
6 2 cv ⊢ 𝑓
7 6 4 wcel ⊢ 𝑓 ∈ Field
8 5 7 wa ⊢ ( 𝑒 ∈ Field ∧ 𝑓 ∈ Field )
9 cress ⊢ ↾s
10 cbs ⊢ Base
11 6 10 cfv ⊢ ( Base ‘ 𝑓 )
12 3 11 9 co ⊢ ( 𝑒 ↾s ( Base ‘ 𝑓 ) )
13 6 12 wceq ⊢ 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) )
14 csubrg ⊢ SubRing
15 3 14 cfv ⊢ ( SubRing ‘ 𝑒 )
16 11 15 wcel ⊢ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 )
17 13 16 wa ⊢ ( 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) ) ∧ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 ) )
18 8 17 wa ⊢ ( ( 𝑒 ∈ Field ∧ 𝑓 ∈ Field ) ∧ ( 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) ) ∧ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 ) ) )
19 18 1 2 copab ⊢ { ⟨ 𝑒 , 𝑓 ⟩ ∣ ( ( 𝑒 ∈ Field ∧ 𝑓 ∈ Field ) ∧ ( 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) ) ∧ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 ) ) ) }
20 0 19 wceq ⊢ /FldExt = { ⟨ 𝑒 , 𝑓 ⟩ ∣ ( ( 𝑒 ∈ Field ∧ 𝑓 ∈ Field ) ∧ ( 𝑓 = ( 𝑒 ↾s ( Base ‘ 𝑓 ) ) ∧ ( Base ‘ 𝑓 ) ∈ ( SubRing ‘ 𝑒 ) ) ) }