Metamath Proof Explorer


Theorem dfid2OLD

Description: Obsolete version of dfid2 as of 4-Nov-2024. (Contributed by NM, 15-Mar-2007) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion dfid2OLD I = { ⟨ 𝑥 , 𝑥 ⟩ ∣ 𝑥 = 𝑥 }

Proof

Step Hyp Ref Expression
1 dfid3 I = { ⟨ 𝑥 , 𝑥 ⟩ ∣ 𝑥 = 𝑥 }