Metamath Proof Explorer


Theorem dia2dimlem4

Description: Lemma for dia2dim . Show that the composition (sum) of translations (vectors) G and D equals F . Part of proof of Lemma M in Crawley p. 121 line 5. (Contributed by NM, 8-Sep-2014)

Ref Expression
Hypotheses dia2dimlem4.l ⊢ ≤ = ( le ‘ 𝐾 )
dia2dimlem4.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
dia2dimlem4.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
dia2dimlem4.t ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 )
dia2dimlem4.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
dia2dimlem4.p ⊢ ( 𝜑 → ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) )
dia2dimlem4.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑇 )
dia2dimlem4.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑇 )
dia2dimlem4.gv ⊢ ( 𝜑 → ( 𝐺 ‘ 𝑃 ) = 𝑄 )
dia2dimlem4.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑇 )
dia2dimlem4.dv ⊢ ( 𝜑 → ( 𝐷 ‘ 𝑄 ) = ( 𝐹 ‘ 𝑃 ) )
Assertion dia2dimlem4 ( 𝜑 → ( 𝐷 ∘ 𝐺 ) = 𝐹 )

Proof

Step Hyp Ref Expression
1 dia2dimlem4.l ⊢ ≤ = ( le ‘ 𝐾 )
2 dia2dimlem4.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
3 dia2dimlem4.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
4 dia2dimlem4.t ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 )
5 dia2dimlem4.k ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) )
6 dia2dimlem4.p ⊢ ( 𝜑 → ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) )
7 dia2dimlem4.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑇 )
8 dia2dimlem4.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑇 )
9 dia2dimlem4.gv ⊢ ( 𝜑 → ( 𝐺 ‘ 𝑃 ) = 𝑄 )
10 dia2dimlem4.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑇 )
11 dia2dimlem4.dv ⊢ ( 𝜑 → ( 𝐷 ‘ 𝑄 ) = ( 𝐹 ‘ 𝑃 ) )
12 3 4 ltrnco ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐷 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) → ( 𝐷 ∘ 𝐺 ) ∈ 𝑇 )
13 5 10 8 12 syl3anc ⊢ ( 𝜑 → ( 𝐷 ∘ 𝐺 ) ∈ 𝑇 )
14 6 simpld ⊢ ( 𝜑 → 𝑃 ∈ 𝐴 )
15 1 2 3 4 ltrncoval ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐷 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ 𝑃 ∈ 𝐴 ) → ( ( 𝐷 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐷 ‘ ( 𝐺 ‘ 𝑃 ) ) )
16 5 10 8 14 15 syl121anc ⊢ ( 𝜑 → ( ( 𝐷 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐷 ‘ ( 𝐺 ‘ 𝑃 ) ) )
17 9 fveq2d ⊢ ( 𝜑 → ( 𝐷 ‘ ( 𝐺 ‘ 𝑃 ) ) = ( 𝐷 ‘ 𝑄 ) )
18 16 17 11 3eqtrd ⊢ ( 𝜑 → ( ( 𝐷 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐹 ‘ 𝑃 ) )
19 1 2 3 4 cdlemd ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐷 ∘ 𝐺 ) ∈ 𝑇 ∧ 𝐹 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( ( 𝐷 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐹 ‘ 𝑃 ) ) → ( 𝐷 ∘ 𝐺 ) = 𝐹 )
20 5 13 7 6 18 19 syl311anc ⊢ ( 𝜑 → ( 𝐷 ∘ 𝐺 ) = 𝐹 )