Metamath Proof Explorer
Description: Deduction adding difference to the right in a class equality.
(Contributed by NM, 15-Nov-2002)
|
|
Ref |
Expression |
|
Hypothesis |
difeq1d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
Assertion |
difeq1d |
⊢ ( 𝜑 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
difeq1d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
2 |
|
difeq1 |
⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) ) |
3 |
1 2
|
syl |
⊢ ( 𝜑 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) ) |