Metamath Proof Explorer


Theorem difeq1i

Description: Inference adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1i.1 𝐴 = 𝐵
Assertion difeq1i ( 𝐴𝐶 ) = ( 𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 difeq1i.1 𝐴 = 𝐵
2 difeq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )
3 1 2 ax-mp ( 𝐴𝐶 ) = ( 𝐵𝐶 )