Metamath Proof Explorer


Theorem dimpropd

Description: If two structures have the same components (properties), they have the same dimension. (Contributed by Thierry Arnoux, 18-May-2023)

Ref Expression
Hypotheses dimpropd.b1 ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐾 ) )
dimpropd.b2 ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐿 ) )
dimpropd.w ⊢ ( 𝜑 → 𝐵 ⊆ 𝑊 )
dimpropd.p ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊 ) ) → ( 𝑥 ( +g ‘ 𝐾 ) 𝑦 ) = ( 𝑥 ( +g ‘ 𝐿 ) 𝑦 ) )
dimpropd.s1 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵 ) ) → ( 𝑥 ( ·𝑠 ‘ 𝐾 ) 𝑦 ) ∈ 𝑊 )
dimpropd.s2 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵 ) ) → ( 𝑥 ( ·𝑠 ‘ 𝐾 ) 𝑦 ) = ( 𝑥 ( ·𝑠 ‘ 𝐿 ) 𝑦 ) )
dimpropd.f ⊢ 𝐹 = ( Scalar ‘ 𝐾 )
dimpropd.g ⊢ 𝐺 = ( Scalar ‘ 𝐿 )
dimpropd.p1 ⊢ ( 𝜑 → 𝑃 = ( Base ‘ 𝐹 ) )
dimpropd.p2 ⊢ ( 𝜑 → 𝑃 = ( Base ‘ 𝐺 ) )
dimpropd.a ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝑃 ) ) → ( 𝑥 ( +g ‘ 𝐹 ) 𝑦 ) = ( 𝑥 ( +g ‘ 𝐺 ) 𝑦 ) )
dimpropd.v1 ⊢ ( 𝜑 → 𝐾 ∈ LVec )
dimpropd.v2 ⊢ ( 𝜑 → 𝐿 ∈ LVec )
Assertion dimpropd ( 𝜑 → ( dim ‘ 𝐾 ) = ( dim ‘ 𝐿 ) )

Proof

Step Hyp Ref Expression
1 dimpropd.b1 ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐾 ) )
2 dimpropd.b2 ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐿 ) )
3 dimpropd.w ⊢ ( 𝜑 → 𝐵 ⊆ 𝑊 )
4 dimpropd.p ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊 ) ) → ( 𝑥 ( +g ‘ 𝐾 ) 𝑦 ) = ( 𝑥 ( +g ‘ 𝐿 ) 𝑦 ) )
5 dimpropd.s1 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵 ) ) → ( 𝑥 ( ·𝑠 ‘ 𝐾 ) 𝑦 ) ∈ 𝑊 )
6 dimpropd.s2 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵 ) ) → ( 𝑥 ( ·𝑠 ‘ 𝐾 ) 𝑦 ) = ( 𝑥 ( ·𝑠 ‘ 𝐿 ) 𝑦 ) )
7 dimpropd.f ⊢ 𝐹 = ( Scalar ‘ 𝐾 )
8 dimpropd.g ⊢ 𝐺 = ( Scalar ‘ 𝐿 )
9 dimpropd.p1 ⊢ ( 𝜑 → 𝑃 = ( Base ‘ 𝐹 ) )
10 dimpropd.p2 ⊢ ( 𝜑 → 𝑃 = ( Base ‘ 𝐺 ) )
11 dimpropd.a ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝑃 ) ) → ( 𝑥 ( +g ‘ 𝐹 ) 𝑦 ) = ( 𝑥 ( +g ‘ 𝐺 ) 𝑦 ) )
12 dimpropd.v1 ⊢ ( 𝜑 → 𝐾 ∈ LVec )
13 dimpropd.v2 ⊢ ( 𝜑 → 𝐿 ∈ LVec )
14 eqid ⊢ ( LBasis ‘ 𝐾 ) = ( LBasis ‘ 𝐾 )
15 14 lbsex ⊢ ( 𝐾 ∈ LVec → ( LBasis ‘ 𝐾 ) ≠ ∅ )
16 12 15 syl ⊢ ( 𝜑 → ( LBasis ‘ 𝐾 ) ≠ ∅ )
17 n0 ⊢ ( ( LBasis ‘ 𝐾 ) ≠ ∅ ↔ ∃ 𝑥 𝑥 ∈ ( LBasis ‘ 𝐾 ) )
18 16 17 sylib ⊢ ( 𝜑 → ∃ 𝑥 𝑥 ∈ ( LBasis ‘ 𝐾 ) )
19 14 dimval ⊢ ( ( 𝐾 ∈ LVec ∧ 𝑥 ∈ ( LBasis ‘ 𝐾 ) ) → ( dim ‘ 𝐾 ) = ( ♯ ‘ 𝑥 ) )
20 12 19 sylan ⊢ ( ( 𝜑 ∧ 𝑥 ∈ ( LBasis ‘ 𝐾 ) ) → ( dim ‘ 𝐾 ) = ( ♯ ‘ 𝑥 ) )
21 1 2 3 4 5 6 7 8 9 10 11 12 13 lbspropd ⊢ ( 𝜑 → ( LBasis ‘ 𝐾 ) = ( LBasis ‘ 𝐿 ) )
22 21 eleq2d ⊢ ( 𝜑 → ( 𝑥 ∈ ( LBasis ‘ 𝐾 ) ↔ 𝑥 ∈ ( LBasis ‘ 𝐿 ) ) )
23 22 biimpa ⊢ ( ( 𝜑 ∧ 𝑥 ∈ ( LBasis ‘ 𝐾 ) ) → 𝑥 ∈ ( LBasis ‘ 𝐿 ) )
24 eqid ⊢ ( LBasis ‘ 𝐿 ) = ( LBasis ‘ 𝐿 )
25 24 dimval ⊢ ( ( 𝐿 ∈ LVec ∧ 𝑥 ∈ ( LBasis ‘ 𝐿 ) ) → ( dim ‘ 𝐿 ) = ( ♯ ‘ 𝑥 ) )
26 13 23 25 syl2an2r ⊢ ( ( 𝜑 ∧ 𝑥 ∈ ( LBasis ‘ 𝐾 ) ) → ( dim ‘ 𝐿 ) = ( ♯ ‘ 𝑥 ) )
27 20 26 eqtr4d ⊢ ( ( 𝜑 ∧ 𝑥 ∈ ( LBasis ‘ 𝐾 ) ) → ( dim ‘ 𝐾 ) = ( dim ‘ 𝐿 ) )
28 18 27 exlimddv ⊢ ( 𝜑 → ( dim ‘ 𝐾 ) = ( dim ‘ 𝐿 ) )