Metamath Proof Explorer


Theorem disj1

Description: Two ways of saying that two classes are disjoint (have no members in common). (Contributed by NM, 19-Aug-1993)

Ref Expression
Assertion disj1 ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥 ( 𝑥𝐴 → ¬ 𝑥𝐵 ) )

Proof

Step Hyp Ref Expression
1 disj ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥𝐴 ¬ 𝑥𝐵 )
2 df-ral ( ∀ 𝑥𝐴 ¬ 𝑥𝐵 ↔ ∀ 𝑥 ( 𝑥𝐴 → ¬ 𝑥𝐵 ) )
3 1 2 bitri ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥 ( 𝑥𝐴 → ¬ 𝑥𝐵 ) )