Metamath Proof Explorer


Theorem disj2

Description: Two ways of saying that two classes are disjoint. (Contributed by NM, 17-May-1998)

Ref Expression
Assertion disj2 ( ( 𝐴𝐵 ) = ∅ ↔ 𝐴 ⊆ ( V ∖ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 ssv 𝐴 ⊆ V
2 reldisj ( 𝐴 ⊆ V → ( ( 𝐴𝐵 ) = ∅ ↔ 𝐴 ⊆ ( V ∖ 𝐵 ) ) )
3 1 2 ax-mp ( ( 𝐴𝐵 ) = ∅ ↔ 𝐴 ⊆ ( V ∖ 𝐵 ) )