Metamath Proof Explorer


Theorem disjdifr

Description: A class and its relative complement are disjoint. (Contributed by Thierry Arnoux, 29-Nov-2023)

Ref Expression
Assertion disjdifr ( ( 𝐵𝐴 ) ∩ 𝐴 ) = ∅

Proof

Step Hyp Ref Expression
1 incom ( 𝐴 ∩ ( 𝐵𝐴 ) ) = ( ( 𝐵𝐴 ) ∩ 𝐴 )
2 disjdif ( 𝐴 ∩ ( 𝐵𝐴 ) ) = ∅
3 1 2 eqtr3i ( ( 𝐵𝐴 ) ∩ 𝐴 ) = ∅