Metamath Proof Explorer


Theorem disjr

Description: Two ways of saying that two classes are disjoint. (Contributed by Jeff Madsen, 19-Jun-2011)

Ref Expression
Assertion disjr ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )

Proof

Step Hyp Ref Expression
1 incom ( 𝐴𝐵 ) = ( 𝐵𝐴 )
2 1 eqeq1i ( ( 𝐴𝐵 ) = ∅ ↔ ( 𝐵𝐴 ) = ∅ )
3 disj ( ( 𝐵𝐴 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )
4 2 3 bitri ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )