Theorem divcan7d

Description: Cancel equal divisors in a division. (Contributed by Mario Carneiro, 27-May-2016)

	Ref	Expression
Hypotheses	div1d.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
	divcld.2	⊢ ( 𝜑 → 𝐵 ∈ ℂ )
	divmuld.3	⊢ ( 𝜑 → 𝐶 ∈ ℂ )
	divmuld.4	⊢ ( 𝜑 → 𝐵 ≠ 0 )
	divdiv23d.5	⊢ ( 𝜑 → 𝐶 ≠ 0 )
Assertion	divcan7d	⊢ ( 𝜑 → ( ( 𝐴 / 𝐶 ) / ( 𝐵 / 𝐶 ) ) = ( 𝐴 / 𝐵 ) )

Proof

Step	Hyp	Ref	Expression
1		div1d.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2		divcld.2	⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3		divmuld.3	⊢ ( 𝜑 → 𝐶 ∈ ℂ )
4		divmuld.4	⊢ ( 𝜑 → 𝐵 ≠ 0 )
5		divdiv23d.5	⊢ ( 𝜑 → 𝐶 ≠ 0 )
6		divcan7	⊢ ( ( 𝐴 ∈ ℂ ∧ ( 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) ∧ ( 𝐶 ∈ ℂ ∧ 𝐶 ≠ 0 ) ) → ( ( 𝐴 / 𝐶 ) / ( 𝐵 / 𝐶 ) ) = ( 𝐴 / 𝐵 ) )
7	1 2 4 3 5 6	syl122anc	⊢ ( 𝜑 → ( ( 𝐴 / 𝐶 ) / ( 𝐵 / 𝐶 ) ) = ( 𝐴 / 𝐵 ) )