Metamath Proof Explorer


Theorem diveq1d

Description: Equality in terms of unit ratio. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses div1d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
divcld.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
divcld.3 ⊢ ( 𝜑 → 𝐵 ≠ 0 )
diveq1d.4 ⊢ ( 𝜑 → ( 𝐴 / 𝐵 ) = 1 )
Assertion diveq1d ( 𝜑 → 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 div1d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 divcld.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 divcld.3 ⊢ ( 𝜑 → 𝐵 ≠ 0 )
4 diveq1d.4 ⊢ ( 𝜑 → ( 𝐴 / 𝐵 ) = 1 )
5 diveq1 ⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = 𝐵 ) )
6 1 2 3 5 syl3anc ⊢ ( 𝜑 → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = 𝐵 ) )
7 4 6 mpbid ⊢ ( 𝜑 → 𝐴 = 𝐵 )