Metamath Proof Explorer


Theorem drgextsubrg

Description: The scalar field is a subring of a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023)

Ref Expression
Hypotheses drgext.b ⊢ 𝐵 = ( ( subringAlg ‘ 𝐸 ) ‘ 𝑈 )
drgext.1 ⊢ ( 𝜑 → 𝐸 ∈ DivRing )
drgext.2 ⊢ ( 𝜑 → 𝑈 ∈ ( SubRing ‘ 𝐸 ) )
drgext.f ⊢ 𝐹 = ( 𝐸 ↾s 𝑈 )
drgext.3 ⊢ ( 𝜑 → 𝐹 ∈ DivRing )
Assertion drgextsubrg ( 𝜑 → 𝑈 ∈ ( SubRing ‘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 drgext.b ⊢ 𝐵 = ( ( subringAlg ‘ 𝐸 ) ‘ 𝑈 )
2 drgext.1 ⊢ ( 𝜑 → 𝐸 ∈ DivRing )
3 drgext.2 ⊢ ( 𝜑 → 𝑈 ∈ ( SubRing ‘ 𝐸 ) )
4 drgext.f ⊢ 𝐹 = ( 𝐸 ↾s 𝑈 )
5 drgext.3 ⊢ ( 𝜑 → 𝐹 ∈ DivRing )
6 1 a1i ⊢ ( 𝜑 → 𝐵 = ( ( subringAlg ‘ 𝐸 ) ‘ 𝑈 ) )
7 eqid ⊢ ( Base ‘ 𝐸 ) = ( Base ‘ 𝐸 )
8 7 subrgss ⊢ ( 𝑈 ∈ ( SubRing ‘ 𝐸 ) → 𝑈 ⊆ ( Base ‘ 𝐸 ) )
9 3 8 syl ⊢ ( 𝜑 → 𝑈 ⊆ ( Base ‘ 𝐸 ) )
10 6 3 9 srasubrg ⊢ ( 𝜑 → 𝑈 ∈ ( SubRing ‘ 𝐵 ) )