Metamath Proof Explorer


Theorem dtru

Description: Given any set (the " y " in the statement), not all sets are equal to it. The same statement without disjoint variable condition is false since it contradicts stdpc6 . The same comments and revision history concerning axiom usage as in exneq apply. (Contributed by NM, 7-Nov-2006) Extract exneq as an intermediate result. (Revised by BJ, 2-Jan-2025)

Ref Expression
Assertion dtru ¬ ∀ 𝑥 𝑥 = 𝑦

Proof

Step Hyp Ref Expression
1 exneq 𝑥 ¬ 𝑥 = 𝑦
2 exnal ( ∃ 𝑥 ¬ 𝑥 = 𝑦 ↔ ¬ ∀ 𝑥 𝑥 = 𝑦 )
3 1 2 mpbi ¬ ∀ 𝑥 𝑥 = 𝑦