Metamath Proof Explorer


Theorem ecase33d

Description: Deduction for elimination by cases. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses ecase33d.1 ⊢ ( 𝜑 → ¬ 𝜓 )
ecase33d.2 ⊢ ( 𝜑 → ¬ 𝜒 )
ecase33d.3 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ∨ 𝜃 ) )
Assertion ecase33d ( 𝜑 → 𝜃 )

Proof

Step Hyp Ref Expression
1 ecase33d.1 ⊢ ( 𝜑 → ¬ 𝜓 )
2 ecase33d.2 ⊢ ( 𝜑 → ¬ 𝜒 )
3 ecase33d.3 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ∨ 𝜃 ) )
4 df-3or ⊢ ( ( 𝜓 ∨ 𝜒 ∨ 𝜃 ) ↔ ( ( 𝜓 ∨ 𝜒 ) ∨ 𝜃 ) )
5 3 4 sylib ⊢ ( 𝜑 → ( ( 𝜓 ∨ 𝜒 ) ∨ 𝜃 ) )
6 ioran ⊢ ( ¬ ( 𝜓 ∨ 𝜒 ) ↔ ( ¬ 𝜓 ∧ ¬ 𝜒 ) )
7 1 2 6 sylanbrc ⊢ ( 𝜑 → ¬ ( 𝜓 ∨ 𝜒 ) )
8 5 7 orcnd ⊢ ( 𝜑 → 𝜃 )