Metamath Proof Explorer


Theorem eldmg

Description: Domain membership. Theorem 4 of Suppes p. 59. (Contributed by Mario Carneiro, 9-Jul-2014)

Ref Expression
Assertion eldmg ( 𝐴𝑉 → ( 𝐴 ∈ dom 𝐵 ↔ ∃ 𝑦 𝐴 𝐵 𝑦 ) )

Proof

Step Hyp Ref Expression
1 breq1 ( 𝑥 = 𝑤 → ( 𝑥 𝐵 𝑦𝑤 𝐵 𝑦 ) )
2 1 exbidv ( 𝑥 = 𝑤 → ( ∃ 𝑦 𝑥 𝐵 𝑦 ↔ ∃ 𝑦 𝑤 𝐵 𝑦 ) )
3 breq1 ( 𝑤 = 𝐴 → ( 𝑤 𝐵 𝑦𝐴 𝐵 𝑦 ) )
4 3 exbidv ( 𝑤 = 𝐴 → ( ∃ 𝑦 𝑤 𝐵 𝑦 ↔ ∃ 𝑦 𝐴 𝐵 𝑦 ) )
5 df-dm dom 𝐵 = { 𝑥 ∣ ∃ 𝑦 𝑥 𝐵 𝑦 }
6 2 4 5 elab2gw ( 𝐴𝑉 → ( 𝐴 ∈ dom 𝐵 ↔ ∃ 𝑦 𝐴 𝐵 𝑦 ) )