Step |
Hyp |
Ref |
Expression |
1 |
|
elimampt.f |
⊢ 𝐹 = ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) |
2 |
|
elimampt.c |
⊢ ( 𝜑 → 𝐶 ∈ 𝑊 ) |
3 |
|
elimampt.d |
⊢ ( 𝜑 → 𝐷 ⊆ 𝐴 ) |
4 |
|
df-ima |
⊢ ( 𝐹 “ 𝐷 ) = ran ( 𝐹 ↾ 𝐷 ) |
5 |
4
|
eleq2i |
⊢ ( 𝐶 ∈ ( 𝐹 “ 𝐷 ) ↔ 𝐶 ∈ ran ( 𝐹 ↾ 𝐷 ) ) |
6 |
1
|
reseq1i |
⊢ ( 𝐹 ↾ 𝐷 ) = ( ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ↾ 𝐷 ) |
7 |
|
resmpt |
⊢ ( 𝐷 ⊆ 𝐴 → ( ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ↾ 𝐷 ) = ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) |
8 |
6 7
|
syl5eq |
⊢ ( 𝐷 ⊆ 𝐴 → ( 𝐹 ↾ 𝐷 ) = ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) |
9 |
8
|
rneqd |
⊢ ( 𝐷 ⊆ 𝐴 → ran ( 𝐹 ↾ 𝐷 ) = ran ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) |
10 |
9
|
eleq2d |
⊢ ( 𝐷 ⊆ 𝐴 → ( 𝐶 ∈ ran ( 𝐹 ↾ 𝐷 ) ↔ 𝐶 ∈ ran ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) ) |
11 |
3 10
|
syl |
⊢ ( 𝜑 → ( 𝐶 ∈ ran ( 𝐹 ↾ 𝐷 ) ↔ 𝐶 ∈ ran ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) ) |
12 |
|
eqid |
⊢ ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) = ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) |
13 |
12
|
elrnmpt |
⊢ ( 𝐶 ∈ 𝑊 → ( 𝐶 ∈ ran ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐷 𝐶 = 𝐵 ) ) |
14 |
2 13
|
syl |
⊢ ( 𝜑 → ( 𝐶 ∈ ran ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐷 𝐶 = 𝐵 ) ) |
15 |
11 14
|
bitrd |
⊢ ( 𝜑 → ( 𝐶 ∈ ran ( 𝐹 ↾ 𝐷 ) ↔ ∃ 𝑥 ∈ 𝐷 𝐶 = 𝐵 ) ) |
16 |
5 15
|
syl5bb |
⊢ ( 𝜑 → ( 𝐶 ∈ ( 𝐹 “ 𝐷 ) ↔ ∃ 𝑥 ∈ 𝐷 𝐶 = 𝐵 ) ) |