Metamath Proof Explorer


Theorem eliun

Description: Membership in indexed union. (Contributed by NM, 3-Sep-2003)

Ref Expression
Assertion eliun ( 𝐴 𝑥𝐵 𝐶 ↔ ∃ 𝑥𝐵 𝐴𝐶 )

Proof

Step Hyp Ref Expression
1 elex ( 𝐴 𝑥𝐵 𝐶𝐴 ∈ V )
2 elex ( 𝐴𝐶𝐴 ∈ V )
3 2 rexlimivw ( ∃ 𝑥𝐵 𝐴𝐶𝐴 ∈ V )
4 eleq1 ( 𝑦 = 𝑤 → ( 𝑦𝐶𝑤𝐶 ) )
5 4 rexbidv ( 𝑦 = 𝑤 → ( ∃ 𝑥𝐵 𝑦𝐶 ↔ ∃ 𝑥𝐵 𝑤𝐶 ) )
6 eleq1 ( 𝑤 = 𝐴 → ( 𝑤𝐶𝐴𝐶 ) )
7 6 rexbidv ( 𝑤 = 𝐴 → ( ∃ 𝑥𝐵 𝑤𝐶 ↔ ∃ 𝑥𝐵 𝐴𝐶 ) )
8 df-iun 𝑥𝐵 𝐶 = { 𝑦 ∣ ∃ 𝑥𝐵 𝑦𝐶 }
9 5 7 8 elab2gw ( 𝐴 ∈ V → ( 𝐴 𝑥𝐵 𝐶 ↔ ∃ 𝑥𝐵 𝐴𝐶 ) )
10 1 3 9 pm5.21nii ( 𝐴 𝑥𝐵 𝐶 ↔ ∃ 𝑥𝐵 𝐴𝐶 )