Metamath Proof Explorer


Theorem elmapfun

Description: A mapping is always a function. (Contributed by Stefan O'Rear, 9-Oct-2014) (Revised by Stefan O'Rear, 5-May-2015)

Ref Expression
Assertion elmapfun ( 𝐴 ∈ ( 𝐵m 𝐶 ) → Fun 𝐴 )

Proof

Step Hyp Ref Expression
1 elmapi ( 𝐴 ∈ ( 𝐵m 𝐶 ) → 𝐴 : 𝐶𝐵 )
2 1 ffund ( 𝐴 ∈ ( 𝐵m 𝐶 ) → Fun 𝐴 )