Metamath Proof Explorer


Theorem elpmi

Description: A partial function is a function. (Contributed by Mario Carneiro, 15-Sep-2015)

Ref Expression
Assertion elpmi ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) → ( 𝐹 : dom 𝐹 ⟶ 𝐴 ∧ dom 𝐹 ⊆ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 n0i ⊢ ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) → ¬ ( 𝐴 ↑pm 𝐵 ) = ∅ )
2 fnpm ⊢ ↑pm Fn ( V × V )
3 2 fndmi ⊢ dom ↑pm = ( V × V )
4 3 ndmov ⊢ ( ¬ ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) → ( 𝐴 ↑pm 𝐵 ) = ∅ )
5 1 4 nsyl2 ⊢ ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) → ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) )
6 elpm2g ⊢ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) → ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) ↔ ( 𝐹 : dom 𝐹 ⟶ 𝐴 ∧ dom 𝐹 ⊆ 𝐵 ) ) )
7 5 6 syl ⊢ ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) → ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) ↔ ( 𝐹 : dom 𝐹 ⟶ 𝐴 ∧ dom 𝐹 ⊆ 𝐵 ) ) )
8 7 ibi ⊢ ( 𝐹 ∈ ( 𝐴 ↑pm 𝐵 ) → ( 𝐹 : dom 𝐹 ⟶ 𝐴 ∧ dom 𝐹 ⊆ 𝐵 ) )