Metamath Proof Explorer


Theorem elpredg

Description: Membership in a predecessor class. (Contributed by Scott Fenton, 17-Apr-2011)

Ref Expression
Assertion elpredg ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑌 ∈ Pred ( 𝑅 , 𝐴 , 𝑋 ) ↔ 𝑌 𝑅 𝑋 ) )

Proof

Step Hyp Ref Expression
1 df-pred Pred ( 𝑅 , 𝐴 , 𝑋 ) = ( 𝐴 ∩ ( 𝑅 “ { 𝑋 } ) )
2 1 elin2 ( 𝑌 ∈ Pred ( 𝑅 , 𝐴 , 𝑋 ) ↔ ( 𝑌𝐴𝑌 ∈ ( 𝑅 “ { 𝑋 } ) ) )
3 2 baib ( 𝑌𝐴 → ( 𝑌 ∈ Pred ( 𝑅 , 𝐴 , 𝑋 ) ↔ 𝑌 ∈ ( 𝑅 “ { 𝑋 } ) ) )
4 3 adantl ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑌 ∈ Pred ( 𝑅 , 𝐴 , 𝑋 ) ↔ 𝑌 ∈ ( 𝑅 “ { 𝑋 } ) ) )
5 elimasng ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑌 ∈ ( 𝑅 “ { 𝑋 } ) ↔ ⟨ 𝑋 , 𝑌 ⟩ ∈ 𝑅 ) )
6 df-br ( 𝑋 𝑅 𝑌 ↔ ⟨ 𝑋 , 𝑌 ⟩ ∈ 𝑅 )
7 5 6 bitr4di ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑌 ∈ ( 𝑅 “ { 𝑋 } ) ↔ 𝑋 𝑅 𝑌 ) )
8 brcnvg ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑋 𝑅 𝑌𝑌 𝑅 𝑋 ) )
9 4 7 8 3bitrd ( ( 𝑋𝐵𝑌𝐴 ) → ( 𝑌 ∈ Pred ( 𝑅 , 𝐴 , 𝑋 ) ↔ 𝑌 𝑅 𝑋 ) )