Metamath Proof Explorer
Description: Obsolete proof of elpwg as of 31-Dec-2023. (Contributed by NM, 6-Aug-2000) (Proof modification is discouraged.)
(New usage is discouraged.)
|
|
Ref |
Expression |
|
Assertion |
elpwgOLD |
⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 ∈ 𝒫 𝐵 ↔ 𝐴 ⊆ 𝐵 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eleq1 |
⊢ ( 𝑥 = 𝐴 → ( 𝑥 ∈ 𝒫 𝐵 ↔ 𝐴 ∈ 𝒫 𝐵 ) ) |
2 |
|
sseq1 |
⊢ ( 𝑥 = 𝐴 → ( 𝑥 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐵 ) ) |
3 |
|
velpw |
⊢ ( 𝑥 ∈ 𝒫 𝐵 ↔ 𝑥 ⊆ 𝐵 ) |
4 |
1 2 3
|
vtoclbg |
⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 ∈ 𝒫 𝐵 ↔ 𝐴 ⊆ 𝐵 ) ) |