Metamath Proof Explorer


Theorem elvv

Description: Membership in universal class of ordered pairs. (Contributed by NM, 4-Jul-1994) (Proof shortened by BJ, 16-Oct-2026)

Ref Expression
Assertion elvv ( 𝐴 ∈ ( V × V ) ↔ ∃ 𝑥 ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )

Proof

Step Hyp Ref Expression
1 elxp2 ⊢ ( 𝐴 ∈ ( V × V ) ↔ ∃ 𝑥 ∈ V ∃ 𝑦 ∈ V 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )
2 rexv ⊢ ( ∃ 𝑥 ∈ V ∃ 𝑦 ∈ V 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ ↔ ∃ 𝑥 ∃ 𝑦 ∈ V 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )
3 rexv ⊢ ( ∃ 𝑦 ∈ V 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ ↔ ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )
4 3 exbii ⊢ ( ∃ 𝑥 ∃ 𝑦 ∈ V 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ ↔ ∃ 𝑥 ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )
5 1 2 4 3bitri ⊢ ( 𝐴 ∈ ( V × V ) ↔ ∃ 𝑥 ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )