Theorem ensymd

Description: Symmetry of equinumerosity. Deduction form of ensym . (Contributed by David Moews, 1-May-2017)

	Ref	Expression
Hypothesis	ensymd.1	⊢ ( 𝜑 → 𝐴 ≈ 𝐵 )
Assertion	ensymd	⊢ ( 𝜑 → 𝐵 ≈ 𝐴 )

Proof

Step	Hyp	Ref	Expression
1		ensymd.1	⊢ ( 𝜑 → 𝐴 ≈ 𝐵 )
2		ensym	⊢ ( 𝐴 ≈ 𝐵 → 𝐵 ≈ 𝐴 )
3	1 2	syl	⊢ ( 𝜑 → 𝐵 ≈ 𝐴 )