Metamath Proof Explorer


Theorem epeli

Description: The membership relation and the membership predicate agree when the "containing" class is a set. Inference associated with epelg . (Contributed by Scott Fenton, 11-Apr-2012)

Ref Expression
Hypothesis epeli.1 ⊢ 𝐵 ∈ V
Assertion epeli ( 𝐴 E 𝐵 ↔ 𝐴 ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 epeli.1 ⊢ 𝐵 ∈ V
2 epelg ⊢ ( 𝐵 ∈ V → ( 𝐴 E 𝐵 ↔ 𝐴 ∈ 𝐵 ) )
3 1 2 ax-mp ⊢ ( 𝐴 E 𝐵 ↔ 𝐴 ∈ 𝐵 )