Metamath Proof Explorer


Theorem eqeng

Description: Equality implies equinumerosity. (Contributed by NM, 26-Oct-2003)

Ref Expression
Assertion eqeng ( 𝐴𝑉 → ( 𝐴 = 𝐵𝐴𝐵 ) )

Proof

Step Hyp Ref Expression
1 enrefg ( 𝐴𝑉𝐴𝐴 )
2 breq2 ( 𝐴 = 𝐵 → ( 𝐴𝐴𝐴𝐵 ) )
3 1 2 syl5ibcom ( 𝐴𝑉 → ( 𝐴 = 𝐵𝐴𝐵 ) )