Metamath Proof Explorer


Theorem eqeq12OLD

Description: Obsolete version of eqeq12 as of 23-Oct-2024. (Contributed by NM, 3-Aug-1994) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion eqeq12OLD ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴 = 𝐶𝐵 = 𝐷 ) )

Proof

Step Hyp Ref Expression
1 eqeq1 ( 𝐴 = 𝐵 → ( 𝐴 = 𝐶𝐵 = 𝐶 ) )
2 eqeq2 ( 𝐶 = 𝐷 → ( 𝐵 = 𝐶𝐵 = 𝐷 ) )
3 1 2 sylan9bb ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴 = 𝐶𝐵 = 𝐷 ) )