Metamath Proof Explorer


Theorem eqeq1i

Description: Inference from equality to equivalence of equalities. (Contributed by NM, 15-Jul-1993)

Ref Expression
Hypothesis eqeq1i.1 𝐴 = 𝐵
Assertion eqeq1i ( 𝐴 = 𝐶𝐵 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqeq1i.1 𝐴 = 𝐵
2 eqeq1 ( 𝐴 = 𝐵 → ( 𝐴 = 𝐶𝐵 = 𝐶 ) )
3 1 2 ax-mp ( 𝐴 = 𝐶𝐵 = 𝐶 )