Metamath Proof Explorer
Description: Equality in terms of 'less than or equal to', 'less than'. (Contributed by NM, 7-Apr-2001)
|
|
Ref |
Expression |
|
Hypotheses |
ltd.1 |
⊢ ( 𝜑 → 𝐴 ∈ ℝ ) |
|
|
ltd.2 |
⊢ ( 𝜑 → 𝐵 ∈ ℝ ) |
|
Assertion |
eqleltd |
⊢ ( 𝜑 → ( 𝐴 = 𝐵 ↔ ( 𝐴 ≤ 𝐵 ∧ ¬ 𝐴 < 𝐵 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ltd.1 |
⊢ ( 𝜑 → 𝐴 ∈ ℝ ) |
2 |
|
ltd.2 |
⊢ ( 𝜑 → 𝐵 ∈ ℝ ) |
3 |
|
eqlelt |
⊢ ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ) → ( 𝐴 = 𝐵 ↔ ( 𝐴 ≤ 𝐵 ∧ ¬ 𝐴 < 𝐵 ) ) ) |
4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → ( 𝐴 = 𝐵 ↔ ( 𝐴 ≤ 𝐵 ∧ ¬ 𝐴 < 𝐵 ) ) ) |