Metamath Proof Explorer


Theorem eqsb1

Description: Substitution for the left-hand side in an equality. Class version of equsb3 . (Contributed by Rodolfo Medina, 28-Apr-2010)

Ref Expression
Assertion eqsb1 ( [ 𝑦 / 𝑥 ] 𝑥 = 𝐴 ↔ 𝑦 = 𝐴 )

Proof

Step Hyp Ref Expression
1 eqeq1 ⊢ ( 𝑥 = 𝑤 → ( 𝑥 = 𝐴 ↔ 𝑤 = 𝐴 ) )
2 eqeq1 ⊢ ( 𝑤 = 𝑦 → ( 𝑤 = 𝐴 ↔ 𝑦 = 𝐴 ) )
3 1 2 sbievw2 ⊢ ( [ 𝑦 / 𝑥 ] 𝑥 = 𝐴 ↔ 𝑦 = 𝐴 )