Metamath Proof Explorer
Description: A chained subclass and equality deduction. (Contributed by Mario
Carneiro, 2-Jan-2017)
|
|
Ref |
Expression |
|
Hypotheses |
eqsstrdi.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
|
eqsstrdi.2 |
⊢ 𝐵 ⊆ 𝐶 |
|
Assertion |
eqsstrdi |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐶 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
eqsstrdi.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
| 2 |
|
eqsstrdi.2 |
⊢ 𝐵 ⊆ 𝐶 |
| 3 |
2
|
a1i |
⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 ) |
| 4 |
1 3
|
eqsstrd |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐶 ) |