Metamath Proof Explorer
Description: Substitution of equality into a subclass relationship. (Contributed by NM, 16-Jul-1995)
|
|
Ref |
Expression |
|
Hypotheses |
eqsstr.1 |
⊢ 𝐴 = 𝐵 |
|
|
eqsstr.2 |
⊢ 𝐵 ⊆ 𝐶 |
|
Assertion |
eqsstri |
⊢ 𝐴 ⊆ 𝐶 |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
eqsstr.1 |
⊢ 𝐴 = 𝐵 |
| 2 |
|
eqsstr.2 |
⊢ 𝐵 ⊆ 𝐶 |
| 3 |
1
|
sseq1i |
⊢ ( 𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶 ) |
| 4 |
2 3
|
mpbir |
⊢ 𝐴 ⊆ 𝐶 |