Metamath Proof Explorer


Theorem eqtr2

Description: A transitive law for class equality. (Contributed by NM, 20-May-2005) (Proof shortened by Andrew Salmon, 25-May-2011) (Proof shortened by Wolf Lammen, 24-Oct-2024)

Ref Expression
Assertion eqtr2 ( ( 𝐴 = 𝐵𝐴 = 𝐶 ) → 𝐵 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqeq1 ( 𝐴 = 𝐵 → ( 𝐴 = 𝐶𝐵 = 𝐶 ) )
2 1 biimpa ( ( 𝐴 = 𝐵𝐴 = 𝐶 ) → 𝐵 = 𝐶 )