Metamath Proof Explorer


Theorem eqtrid

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses eqtrid.1 ⊢ 𝐴 = 𝐵
eqtrid.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion eqtrid ( 𝜑 → 𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqtrid.1 ⊢ 𝐴 = 𝐵
2 eqtrid.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
3 1 a1i ⊢ ( 𝜑 → 𝐴 = 𝐵 )
4 3 2 eqtrd ⊢ ( 𝜑 → 𝐴 = 𝐶 )