Metamath Proof Explorer


Theorem equequ1

Description: An equivalence law for equality. (Contributed by NM, 1-Aug-1993) (Proof shortened by Wolf Lammen, 10-Dec-2017)

Ref Expression
Assertion equequ1 ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧𝑦 = 𝑧 ) )

Proof

Step Hyp Ref Expression
1 ax7 ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧𝑦 = 𝑧 ) )
2 equtr ( 𝑥 = 𝑦 → ( 𝑦 = 𝑧𝑥 = 𝑧 ) )
3 1 2 impbid ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧𝑦 = 𝑧 ) )