Metamath Proof Explorer


Theorem equs4v

Description: Version of equs4 with a disjoint variable condition, which requires fewer axioms. (Contributed by NM, 10-May-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Assertion equs4v ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) )

Proof

Step Hyp Ref Expression
1 ax6ev 𝑥 𝑥 = 𝑦
2 exintr ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ( ∃ 𝑥 𝑥 = 𝑦 → ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) )
3 1 2 mpi ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) )