Metamath Proof Explorer


Theorem equsalv

Description: An equivalence related to implicit substitution. Version of equsal with a disjoint variable condition, which does not require ax-13 . See equsalvw for a version with two disjoint variable conditions requiring fewer axioms. See also the dual form equsexv . (Contributed by NM, 2-Jun-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses equsalv.nf 𝑥 𝜓
equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion equsalv ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )

Proof

Step Hyp Ref Expression
1 equsalv.nf 𝑥 𝜓
2 equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 1 19.23 ( ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ↔ ( ∃ 𝑥 𝑥 = 𝑦𝜓 ) )
4 2 pm5.74i ( ( 𝑥 = 𝑦𝜑 ) ↔ ( 𝑥 = 𝑦𝜓 ) )
5 4 albii ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) )
6 ax6ev 𝑥 𝑥 = 𝑦
7 6 a1bi ( 𝜓 ↔ ( ∃ 𝑥 𝑥 = 𝑦𝜓 ) )
8 3 5 7 3bitr4i ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )