Metamath Proof Explorer


Theorem equsexv

Description: An equivalence related to implicit substitution. Version of equsex with a disjoint variable condition, which does not require ax-13 . See equsexvw for a version with two disjoint variable conditions requiring fewer axioms. See also the dual form equsalv . (Contributed by NM, 5-Aug-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses equsalv.nf 𝑥 𝜓
equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion equsexv ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )

Proof

Step Hyp Ref Expression
1 equsalv.nf 𝑥 𝜓
2 equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 2 pm5.32i ( ( 𝑥 = 𝑦𝜑 ) ↔ ( 𝑥 = 𝑦𝜓 ) )
4 3 exbii ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ ∃ 𝑥 ( 𝑥 = 𝑦𝜓 ) )
5 ax6ev 𝑥 𝑥 = 𝑦
6 1 19.41 ( ∃ 𝑥 ( 𝑥 = 𝑦𝜓 ) ↔ ( ∃ 𝑥 𝑥 = 𝑦𝜓 ) )
7 5 6 mpbiran ( ∃ 𝑥 ( 𝑥 = 𝑦𝜓 ) ↔ 𝜓 )
8 4 7 bitri ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )