Metamath Proof Explorer


Theorem eqvinc

Description: A variable introduction law for class equality. (Contributed by NM, 14-Apr-1995) (Proof shortened by Andrew Salmon, 8-Jun-2011) (Proof shortened by Thierry Arnoux, 23-Jan-2022)

Ref Expression
Hypothesis eqvinc.1 𝐴 ∈ V
Assertion eqvinc ( 𝐴 = 𝐵 ↔ ∃ 𝑥 ( 𝑥 = 𝐴𝑥 = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 eqvinc.1 𝐴 ∈ V
2 eqvincg ( 𝐴 ∈ V → ( 𝐴 = 𝐵 ↔ ∃ 𝑥 ( 𝑥 = 𝐴𝑥 = 𝐵 ) ) )
3 1 2 ax-mp ( 𝐴 = 𝐵 ↔ ∃ 𝑥 ( 𝑥 = 𝐴𝑥 = 𝐵 ) )