Metamath Proof Explorer


Theorem etransclem42

Description: The N -th derivative of F applied to J is an integer. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses etransclem42.s ⊢ ( 𝜑 → 𝑆 ∈ { ℝ , ℂ } )
etransclem42.x ⊢ ( 𝜑 → 𝑋 ∈ ( ( TopOpen ‘ ℂfld ) ↾t 𝑆 ) )
etransclem42.p ⊢ ( 𝜑 → 𝑃 ∈ ℕ )
etransclem42.m ⊢ ( 𝜑 → 𝑀 ∈ ℕ0 )
etransclem42.f ⊢ 𝐹 = ( 𝑥 ∈ 𝑋 ↦ ( ( 𝑥 ↑ ( 𝑃 − 1 ) ) · ∏ 𝑗 ∈ ( 1 ... 𝑀 ) ( ( 𝑥 − 𝑗 ) ↑ 𝑃 ) ) )
etransclem42.n ⊢ ( 𝜑 → 𝑁 ∈ ℕ0 )
etransclem42.jx ⊢ ( 𝜑 → 𝐽 ∈ 𝑋 )
etransclem42.jz ⊢ ( 𝜑 → 𝐽 ∈ ℤ )
Assertion etransclem42 ( 𝜑 → ( ( ( 𝑆 D𝑛 𝐹 ) ‘ 𝑁 ) ‘ 𝐽 ) ∈ ℤ )

Proof

Step Hyp Ref Expression
1 etransclem42.s ⊢ ( 𝜑 → 𝑆 ∈ { ℝ , ℂ } )
2 etransclem42.x ⊢ ( 𝜑 → 𝑋 ∈ ( ( TopOpen ‘ ℂfld ) ↾t 𝑆 ) )
3 etransclem42.p ⊢ ( 𝜑 → 𝑃 ∈ ℕ )
4 etransclem42.m ⊢ ( 𝜑 → 𝑀 ∈ ℕ0 )
5 etransclem42.f ⊢ 𝐹 = ( 𝑥 ∈ 𝑋 ↦ ( ( 𝑥 ↑ ( 𝑃 − 1 ) ) · ∏ 𝑗 ∈ ( 1 ... 𝑀 ) ( ( 𝑥 − 𝑗 ) ↑ 𝑃 ) ) )
6 etransclem42.n ⊢ ( 𝜑 → 𝑁 ∈ ℕ0 )
7 etransclem42.jx ⊢ ( 𝜑 → 𝐽 ∈ 𝑋 )
8 etransclem42.jz ⊢ ( 𝜑 → 𝐽 ∈ ℤ )
9 etransclem5 ⊢ ( 𝑘 ∈ ( 0 ... 𝑀 ) ↦ ( 𝑦 ∈ 𝑋 ↦ ( ( 𝑦 − 𝑘 ) ↑ if ( 𝑘 = 0 , ( 𝑃 − 1 ) , 𝑃 ) ) ) ) = ( 𝑗 ∈ ( 0 ... 𝑀 ) ↦ ( 𝑥 ∈ 𝑋 ↦ ( ( 𝑥 − 𝑗 ) ↑ if ( 𝑗 = 0 , ( 𝑃 − 1 ) , 𝑃 ) ) ) )
10 etransclem11 ⊢ ( 𝑚 ∈ ℕ0 ↦ { 𝑑 ∈ ( ( 0 ... 𝑚 ) ↑m ( 0 ... 𝑀 ) ) ∣ Σ 𝑘 ∈ ( 0 ... 𝑀 ) ( 𝑑 ‘ 𝑘 ) = 𝑚 } ) = ( 𝑛 ∈ ℕ0 ↦ { 𝑐 ∈ ( ( 0 ... 𝑛 ) ↑m ( 0 ... 𝑀 ) ) ∣ Σ 𝑗 ∈ ( 0 ... 𝑀 ) ( 𝑐 ‘ 𝑗 ) = 𝑛 } )
11 1 2 3 4 5 6 9 7 8 10 etransclem36 ⊢ ( 𝜑 → ( ( ( 𝑆 D𝑛 𝐹 ) ‘ 𝑁 ) ‘ 𝐽 ) ∈ ℤ )