Metamath Proof Explorer


Theorem eupthcl

Description: An Eulerian path has length # ( F ) , which is an integer. (Contributed by Mario Carneiro, 12-Mar-2015) (Revised by AV, 18-Feb-2021)

Ref Expression
Assertion eupthcl ( 𝐹 ( EulerPaths ‘ 𝐺 ) 𝑃 → ( ♯ ‘ 𝐹 ) ∈ ℕ0 )

Proof

Step Hyp Ref Expression
1 eqid ( iEdg ‘ 𝐺 ) = ( iEdg ‘ 𝐺 )
2 1 eupthi ( 𝐹 ( EulerPaths ‘ 𝐺 ) 𝑃 → ( 𝐹 ( Walks ‘ 𝐺 ) 𝑃𝐹 : ( 0 ..^ ( ♯ ‘ 𝐹 ) ) –1-1-onto→ dom ( iEdg ‘ 𝐺 ) ) )
3 wlkcl ( 𝐹 ( Walks ‘ 𝐺 ) 𝑃 → ( ♯ ‘ 𝐹 ) ∈ ℕ0 )
4 3 adantr ( ( 𝐹 ( Walks ‘ 𝐺 ) 𝑃𝐹 : ( 0 ..^ ( ♯ ‘ 𝐹 ) ) –1-1-onto→ dom ( iEdg ‘ 𝐺 ) ) → ( ♯ ‘ 𝐹 ) ∈ ℕ0 )
5 2 4 syl ( 𝐹 ( EulerPaths ‘ 𝐺 ) 𝑃 → ( ♯ ‘ 𝐹 ) ∈ ℕ0 )