Metamath Proof Explorer


Theorem exp5o

Description: A triple exportation inference. (Contributed by Jeff Hankins, 8-Jul-2009)

Ref Expression
Hypothesis exp5o.1 ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) )
Assertion exp5o ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 exp5o.1 ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) )
2 1 expd ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ( 𝜃 → ( 𝜏 → 𝜂 ) ) )
3 2 3exp ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )