Metamath Proof Explorer


Theorem f1oeq23

Description: Equality theorem for one-to-one onto functions. (Contributed by FL, 14-Jul-2012)

Ref Expression
Assertion f1oeq23 ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐷 ) )

Proof

Step Hyp Ref Expression
1 f1oeq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )
2 f1oeq3 ⊢ ( 𝐶 = 𝐷 → ( 𝐹 : 𝐵 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐷 ) )
3 1 2 sylan9bb ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐷 ) )