Metamath Proof Explorer


Theorem f1resrcmplf1dlem

Description: Lemma for f1resrcmplf1d . (Contributed by BTernaryTau, 27-Sep-2023) (Revised by Mingli Yuan, 15-Aug-2026)

Ref Expression
Hypotheses f1resrcmplf1dlem.1 ( 𝜑𝐶𝐴 )
f1resrcmplf1dlem.2 ( 𝜑𝐷𝐴 )
f1resrcmplf1dlem.3 ( 𝜑𝐹 : 𝐴𝐵 )
f1resrcmplf1dlem.4 ( 𝜑 → ( ( 𝐹𝐶 ) ∩ ( 𝐹𝐷 ) ) = ∅ )
f1resrcmplf1dlem.x ( 𝜑𝑋𝐶 )
f1resrcmplf1dlem.y ( 𝜑𝑌𝐷 )
f1resrcmplf1dlem.5 ( 𝜑 → ( 𝐹𝑋 ) = ( 𝐹𝑌 ) )
Assertion f1resrcmplf1dlem ( 𝜑𝑋 = 𝑌 )

Proof

Step Hyp Ref Expression
1 f1resrcmplf1dlem.1 ( 𝜑𝐶𝐴 )
2 f1resrcmplf1dlem.2 ( 𝜑𝐷𝐴 )
3 f1resrcmplf1dlem.3 ( 𝜑𝐹 : 𝐴𝐵 )
4 f1resrcmplf1dlem.4 ( 𝜑 → ( ( 𝐹𝐶 ) ∩ ( 𝐹𝐷 ) ) = ∅ )
5 f1resrcmplf1dlem.x ( 𝜑𝑋𝐶 )
6 f1resrcmplf1dlem.y ( 𝜑𝑌𝐷 )
7 f1resrcmplf1dlem.5 ( 𝜑 → ( 𝐹𝑋 ) = ( 𝐹𝑌 ) )
8 5 6 jca ( 𝜑 → ( 𝑋𝐶𝑌𝐷 ) )
9 3 ffnd ( 𝜑𝐹 Fn 𝐴 )
10 fnfvima ( ( 𝐹 Fn 𝐴𝐶𝐴𝑋𝐶 ) → ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) )
11 9 10 syl3an1 ( ( 𝜑𝐶𝐴𝑋𝐶 ) → ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) )
12 1 11 syl3an2 ( ( 𝜑𝜑𝑋𝐶 ) → ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) )
13 12 3anidm12 ( ( 𝜑𝑋𝐶 ) → ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) )
14 13 ex ( 𝜑 → ( 𝑋𝐶 → ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) ) )
15 fnfvima ( ( 𝐹 Fn 𝐴𝐷𝐴𝑌𝐷 ) → ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) )
16 9 15 syl3an1 ( ( 𝜑𝐷𝐴𝑌𝐷 ) → ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) )
17 2 16 syl3an2 ( ( 𝜑𝜑𝑌𝐷 ) → ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) )
18 17 3anidm12 ( ( 𝜑𝑌𝐷 ) → ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) )
19 18 ex ( 𝜑 → ( 𝑌𝐷 → ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) ) )
20 disjne ( ( ( ( 𝐹𝐶 ) ∩ ( 𝐹𝐷 ) ) = ∅ ∧ ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) ∧ ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) ) → ( 𝐹𝑋 ) ≠ ( 𝐹𝑌 ) )
21 4 20 syl3an1 ( ( 𝜑 ∧ ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) ∧ ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) ) → ( 𝐹𝑋 ) ≠ ( 𝐹𝑌 ) )
22 21 3expib ( 𝜑 → ( ( ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) ∧ ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) ) → ( 𝐹𝑋 ) ≠ ( 𝐹𝑌 ) ) )
23 neneq ( ( 𝐹𝑋 ) ≠ ( 𝐹𝑌 ) → ¬ ( 𝐹𝑋 ) = ( 𝐹𝑌 ) )
24 23 pm2.21d ( ( 𝐹𝑋 ) ≠ ( 𝐹𝑌 ) → ( ( 𝐹𝑋 ) = ( 𝐹𝑌 ) → 𝑋 = 𝑌 ) )
25 22 24 syl6 ( 𝜑 → ( ( ( 𝐹𝑋 ) ∈ ( 𝐹𝐶 ) ∧ ( 𝐹𝑌 ) ∈ ( 𝐹𝐷 ) ) → ( ( 𝐹𝑋 ) = ( 𝐹𝑌 ) → 𝑋 = 𝑌 ) ) )
26 14 19 25 syl2and ( 𝜑 → ( ( 𝑋𝐶𝑌𝐷 ) → ( ( 𝐹𝑋 ) = ( 𝐹𝑌 ) → 𝑋 = 𝑌 ) ) )
27 8 26 mpd ( 𝜑 → ( ( 𝐹𝑋 ) = ( 𝐹𝑌 ) → 𝑋 = 𝑌 ) )
28 7 27 mpd ( 𝜑𝑋 = 𝑌 )