Metamath Proof Explorer


Theorem f2ndres

Description: Mapping of a restriction of the 2nd (second member of an ordered pair) function. (Contributed by NM, 7-Aug-2006) (Revised by Mario Carneiro, 8-Sep-2013)

Ref Expression
Assertion f2ndres ( 2nd ↾ ( 𝐴 × 𝐵 ) ) : ( 𝐴 × 𝐵 ) ⟶ 𝐵

Proof

Step Hyp Ref Expression
1 vex 𝑦 ∈ V
2 vex 𝑧 ∈ V
3 1 2 op2nda ran { ⟨ 𝑦 , 𝑧 ⟩ } = 𝑧
4 3 eleq1i ( ran { ⟨ 𝑦 , 𝑧 ⟩ } ∈ 𝐵𝑧𝐵 )
5 4 bilanri ( ( 𝑦𝐴𝑧𝐵 ) → ran { ⟨ 𝑦 , 𝑧 ⟩ } ∈ 𝐵 )
6 5 rgen2 𝑦𝐴𝑧𝐵 ran { ⟨ 𝑦 , 𝑧 ⟩ } ∈ 𝐵
7 sneq ( 𝑥 = ⟨ 𝑦 , 𝑧 ⟩ → { 𝑥 } = { ⟨ 𝑦 , 𝑧 ⟩ } )
8 7 rneqd ( 𝑥 = ⟨ 𝑦 , 𝑧 ⟩ → ran { 𝑥 } = ran { ⟨ 𝑦 , 𝑧 ⟩ } )
9 8 unieqd ( 𝑥 = ⟨ 𝑦 , 𝑧 ⟩ → ran { 𝑥 } = ran { ⟨ 𝑦 , 𝑧 ⟩ } )
10 9 eleq1d ( 𝑥 = ⟨ 𝑦 , 𝑧 ⟩ → ( ran { 𝑥 } ∈ 𝐵 ran { ⟨ 𝑦 , 𝑧 ⟩ } ∈ 𝐵 ) )
11 10 ralxp ( ∀ 𝑥 ∈ ( 𝐴 × 𝐵 ) ran { 𝑥 } ∈ 𝐵 ↔ ∀ 𝑦𝐴𝑧𝐵 ran { ⟨ 𝑦 , 𝑧 ⟩ } ∈ 𝐵 )
12 6 11 mpbir 𝑥 ∈ ( 𝐴 × 𝐵 ) ran { 𝑥 } ∈ 𝐵
13 df-2nd 2nd = ( 𝑥 ∈ V ↦ ran { 𝑥 } )
14 13 reseq1i ( 2nd ↾ ( 𝐴 × 𝐵 ) ) = ( ( 𝑥 ∈ V ↦ ran { 𝑥 } ) ↾ ( 𝐴 × 𝐵 ) )
15 ssv ( 𝐴 × 𝐵 ) ⊆ V
16 resmpt ( ( 𝐴 × 𝐵 ) ⊆ V → ( ( 𝑥 ∈ V ↦ ran { 𝑥 } ) ↾ ( 𝐴 × 𝐵 ) ) = ( 𝑥 ∈ ( 𝐴 × 𝐵 ) ↦ ran { 𝑥 } ) )
17 15 16 ax-mp ( ( 𝑥 ∈ V ↦ ran { 𝑥 } ) ↾ ( 𝐴 × 𝐵 ) ) = ( 𝑥 ∈ ( 𝐴 × 𝐵 ) ↦ ran { 𝑥 } )
18 14 17 eqtri ( 2nd ↾ ( 𝐴 × 𝐵 ) ) = ( 𝑥 ∈ ( 𝐴 × 𝐵 ) ↦ ran { 𝑥 } )
19 18 fmpt ( ∀ 𝑥 ∈ ( 𝐴 × 𝐵 ) ran { 𝑥 } ∈ 𝐵 ↔ ( 2nd ↾ ( 𝐴 × 𝐵 ) ) : ( 𝐴 × 𝐵 ) ⟶ 𝐵 )
20 12 19 mpbi ( 2nd ↾ ( 𝐴 × 𝐵 ) ) : ( 𝐴 × 𝐵 ) ⟶ 𝐵