Metamath Proof Explorer


Theorem fczfsuppd

Description: A constant function with value zero is finitely supported. (Contributed by AV, 30-Jun-2019)

Ref Expression
Hypotheses fczfsuppd.b ( 𝜑𝐵𝑉 )
fczfsuppd.z ( 𝜑𝑍𝑊 )
Assertion fczfsuppd ( 𝜑 → ( 𝐵 × { 𝑍 } ) finSupp 𝑍 )

Proof

Step Hyp Ref Expression
1 fczfsuppd.b ( 𝜑𝐵𝑉 )
2 fczfsuppd.z ( 𝜑𝑍𝑊 )
3 snex { 𝑍 } ∈ V
4 xpexg ( ( 𝐵𝑉 ∧ { 𝑍 } ∈ V ) → ( 𝐵 × { 𝑍 } ) ∈ V )
5 1 3 4 sylancl ( 𝜑 → ( 𝐵 × { 𝑍 } ) ∈ V )
6 fnconstg ( 𝑍𝑊 → ( 𝐵 × { 𝑍 } ) Fn 𝐵 )
7 fnfun ( ( 𝐵 × { 𝑍 } ) Fn 𝐵 → Fun ( 𝐵 × { 𝑍 } ) )
8 2 6 7 3syl ( 𝜑 → Fun ( 𝐵 × { 𝑍 } ) )
9 fczsupp0 ( ( 𝐵 × { 𝑍 } ) supp 𝑍 ) = ∅
10 0fi ∅ ∈ Fin
11 9 10 eqeltri ( ( 𝐵 × { 𝑍 } ) supp 𝑍 ) ∈ Fin
12 11 a1i ( 𝜑 → ( ( 𝐵 × { 𝑍 } ) supp 𝑍 ) ∈ Fin )
13 5 2 8 12 isfsuppd ( 𝜑 → ( 𝐵 × { 𝑍 } ) finSupp 𝑍 )