Metamath Proof Explorer


Theorem fden

Description: Canonical denominator defines a function. (Contributed by Stefan O'Rear, 13-Sep-2014)

Ref Expression
Assertion fden denom : ℚ ⟶ ℕ

Proof

Step Hyp Ref Expression
1 df-denom denom = ( 𝑎 ∈ ℚ ↦ ( 2nd ‘ ( 𝑏 ∈ ( ℤ × ℕ ) ( ( ( 1st𝑏 ) gcd ( 2nd𝑏 ) ) = 1 ∧ 𝑎 = ( ( 1st𝑏 ) / ( 2nd𝑏 ) ) ) ) ) )
2 qdenval ( 𝑎 ∈ ℚ → ( denom ‘ 𝑎 ) = ( 2nd ‘ ( 𝑏 ∈ ( ℤ × ℕ ) ( ( ( 1st𝑏 ) gcd ( 2nd𝑏 ) ) = 1 ∧ 𝑎 = ( ( 1st𝑏 ) / ( 2nd𝑏 ) ) ) ) ) )
3 qdencl ( 𝑎 ∈ ℚ → ( denom ‘ 𝑎 ) ∈ ℕ )
4 2 3 eqeltrrd ( 𝑎 ∈ ℚ → ( 2nd ‘ ( 𝑏 ∈ ( ℤ × ℕ ) ( ( ( 1st𝑏 ) gcd ( 2nd𝑏 ) ) = 1 ∧ 𝑎 = ( ( 1st𝑏 ) / ( 2nd𝑏 ) ) ) ) ) ∈ ℕ )
5 1 4 fmpti denom : ℚ ⟶ ℕ